4x^2+12y^2-19xy=0

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Solution for 4x^2+12y^2-19xy=0 equation:


Simplifying
4x2 + 12y2 + -19xy = 0

Reorder the terms:
-19xy + 4x2 + 12y2 = 0

Solving
-19xy + 4x2 + 12y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(x + -4y)(4x + -3y) = 0

Subproblem 1

Set the factor '(x + -4y)' equal to zero and attempt to solve: Simplifying x + -4y = 0 Solving x + -4y = 0 Move all terms containing x to the left, all other terms to the right. Add '4y' to each side of the equation. x + -4y + 4y = 0 + 4y Combine like terms: -4y + 4y = 0 x + 0 = 0 + 4y x = 0 + 4y Remove the zero: x = 4y Simplifying x = 4y

Subproblem 2

Set the factor '(4x + -3y)' equal to zero and attempt to solve: Simplifying 4x + -3y = 0 Solving 4x + -3y = 0 Move all terms containing x to the left, all other terms to the right. Add '3y' to each side of the equation. 4x + -3y + 3y = 0 + 3y Combine like terms: -3y + 3y = 0 4x + 0 = 0 + 3y 4x = 0 + 3y Remove the zero: 4x = 3y Divide each side by '4'. x = 0.75y Simplifying x = 0.75y

Solution

x = {4y, 0.75y}

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